A metal was found to have its threshold frequency equal to 10^15 s hertz . If the same metal is irradiated with radiations of frequencies 1.5 * 10^15 herts and 2.5 * 10^15 hertz respectively, the ratio of maximum kinetic energies will be
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Let the threshold frequency is = V
0
V
1
=4×10
15
Hz
V
2
=6×10
15
Hz
now (KE)
1
=hV
1
−hV
0
(KE)
2
=hV
2
−hV
0
Given
hV
2
−hV
0
hV
1
−hV
0
=
3
1
3V
1
−3V
0
=V
2
−V
0
2
(3V
1
−V
2
)
=V
0
V
0
=3×10
15
Hz
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