Question

A metal weighing 0.43 gram was dissolved in 50 ml of 1 Newton H2 s o4 the unreacted H2 S o4 required 14.2 ml of 1 Newton n a o h for neutralization the equivalent weight of the metal is​

Answer 1

ANSWER:21.5g

EXPLANATION

weight of metal= 0.43g

it was dissolved in water=50ml

equilant weight of metal=21.5

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Answer 2

$\huge\mathbb\blue{Question}$

A metal weighing 0.43 gram was dissolved in 50 ml of 1 Newton H2 s o4 the unreacted H2 S o4 required 14.2 ml of 1 Newton n a o h for neutralization the equivalent weight of the metal is ?

$\huge\mathbf\orange{Answer}$

Given

weight of metal= 0.43g

it was dissolved in water=50ml

required = 14.2 ml of 1 N

n a o h for neutralization the equivalent weight of the metal is = 21 . 5 gram

Explanation:

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