Question

a metal weighing 0.43 gram was dissolved in 50 ml of 1 Newton H2 s o4 the unreacted H2 S o4 required 14.2 ml of 1 Newton n a o h for neutralization the equivalent weight of the metal is​

Answer 1

what is the volume of water to be added to 200 ml of 18 molar H2 S o4 solution to get 18 1.8 molar H2 S o4 solution?

98% by weight means 98 gm H2SO4 in 100 gm solution or 98 g H2SO4 in 2 g water.

5.5 [0.1×1000/ 18] So the required volume is 5.5 ml.