Chemistry, asked by parmarthsharma, 8 months ago

A metal weighing 0.43 gram was dissolved in 50 ml of 1 N H2 s o4 the unreacted H2 S o4 required 14.2 ml of 1 N n a o h for neutralization the equivalent weight of the metal is​
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Answered by AwesomeSoul47
18

\huge\mathbb\orange{Question}

A metal weighing 0.43 gram was dissolved in 50 ml of 1 N H2 s o4 the unreacted H2 S o4 required 14.2 ml of 1 N n a o h for neutralization the equivalent weight of the metal is ?

\huge\mathbf\pink{ Required \: answer \: - }

Weight of metal = 0 .43 gram

Dissolved in H2SO4 = 50 ml / N

required 14.2 ml of 1 N

n a o h for neutralization the equivalent weight of the metal is = 21 . 5 gram

\large\underline\red{\sf hope \: it's \: helpful \: for \: you . }

\huge\mathbb\blue{MrRavi47}

Answered by Anonymous
1

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Weight of metal = 0 .43 gram

Dissolved in H2SO4 = 50 ml / N

required 14.2 ml of 1 N

n a o h for neutralization the equivalent weight of the metal is = 21 . 5 gram

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