A metal weighing 50.0 g absorbs 220.0 j of heat when its temperature increases by 120.0c. What is the specific heat of the metal?
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Answer:
m = 50g = 0.05 Kg
Q = 220 J
ΔT = 120°C
c = Q / (ΔT) (m) = 220 / (120) (0.05)
= 36.66 J / Kg K --> Specific Heat of Metal
Explanation:
m is Mass of Metal
Q is the heat absorbed
ΔT is the change in Temperature
c is the Specific heat
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