Question

A metal weighing 50.0 g absorbs 220.0 j of heat when its temperature increases by 120.0c. What is the specific heat of the metal?

Answer 1

Answer:

m = 50g = 0.05 Kg

Q = 220 J

ΔT = 120°C

c = Q / (ΔT) (m) = 220 / (120) (0.05)

= 36.66 J / Kg K --> Specific Heat of Metal

Explanation:

m is Mass of Metal

Q is the heat absorbed

ΔT is the change in Temperature

c is the Specific heat