A metal wire 36cm long is bent to form a rectangle find its dimensions when its area is maximum
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Let the length and breadth of a rectangle be I and b.
.. Perimeter of rectangle = 2 (1 + b) =
36cm
.:. 1+b=18
Area of rectangle = 1x b = 1 (18-1)
Let f(1) = 181-12
f(1) = 18-21
and f(1) = -2
Consider, f '(I) = 0
.. 18-21 0
.. 18 = 21
l= 9
For 1 = 9,
f"(9) = -2 <0
.. f(x), i.e. area is maximum when I
cm
and b = 18-9 [form (i)]
= 9 cm
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