A metal wire is 2.5 mm diameter and 2 meters long. A force of 12 N is applied to it and it stretches 0.3 mm. Assume the material is elastic. Determine the stress in the wire. (Stress= F/A)
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Answered by
4
Answer:
0.75 is the actual material elastic which stress in the wire
Answered by
0
Answer:
Explanation:
d=2.5mm A=3.14*2.5*2.5/4=0.000004905m sq
L=2m F=12N stress=12/0.000004905=2445859.87N/mmsq strain=0.0003/2=0.00015
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