A metal wire of length 40 cm is moulded into a square. Then
the same wire is moulded into a rectangle with length 12 cm.
Find the figure with greater area.
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1
Answer:
the greater figure with area is square = side of a square = 40 cm
area of square =sxs
=40x40
=1600cm²
area of rectangle = lxb
=p/2-length = breadth
=40/2-length
=8 cm breadth
area = 12x8
=96cm²
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Step-by-step explanation:
length of wire =40 cm
every side of square is equal and it has 4 sides so we'll divide it by 4 i.e. side of square=40÷4 =10 cm
therefore area of square will be = side ×side
=10×10 =100cm²
the length of wire would be the perimeter of rectangle and the length 12cm is given
so, perimeter of rectangle = 2( l+b)
40 = 2 ( 12 + b)
20 =12+b
20-12 = b
8cm = b
area of rectangle = l × b
= 12×8
= 96 cm²
so , rectangle will have larger area.
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