Question

A metal wire with specific resistance 1.84×10^-8 ohm metre and length 1 m has a resistance 26 ohm find the radius of the wire ?<br /><br />(Warning :- Don't give nonsense answer and the answer should be clear and understandable !)

Answer 1

Hey
HERE IS YOUR ANSWER
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Resistance=resistivity*length/area
26=1.84*10^-8*1/area
area=1.84*10^-8/26
area=0.07*10^-8=7*10^-10

now area=pi*r^2
7*10^-10=pi*r^2
2.22*10^-10=r^2
therefore
r=1.48*10^-5
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HOPE THIS WILL HELP
PLEASE MARK IT AS BRAINLIEST

Answer 2

Answer:

$The \: Radius \: Of \: Wire = 1.5 \times {10}^{ - 5} m$

Explanation:

Given :-

• Resistance ( R ) = 26 Ω
• Resistivity ( ρ ) = 1.84 × 10^-8 Ωm
• Length of wire ( l ) = 1 m

Solution :-

We know the formula of resistance

$\: \: \: \: \: \: \: R=ρl/A$

Putting all given values ,

$26 = \frac{1.84 \times {10}^{ - 8} }{A}$

$26A = 1.84 \times {10}^{ - 8}$

$A = \frac{1.86 \times {10}^{ - 8} }{26}$

$A = 7.08 \times {10}^{ - 10} \: \: {m}^{2}$

Now ,

radius of the wire can easily be calculated by area

$\pi {r}^{2} = 7.08 \times {10}^{ - 10} {m}^{2}$

$3.14 \times {r}^{2} = 7.08 \times {10}^{ - 10} {m}^{2}$

${r}^{2} = \frac{7.08 \times {10}^{ - 10}}{3.14} {m}^{2}$

${r}^{2} = 2.25 \times {10}^{ - 10} {m}^{2}$

$r = \sqrt{2.25 \times {10}^{ - 10} \: {m}^{2} }$

$r = 1.5 \times {10}^{ - 5} m$

Hence , the radius of the wire = 1.5 × 10^-5