Question

A metal with photoelectric work function 2.1 ev is irradiated with a 1 mw mono chromatic light source of frequency 1 x 1015 hz. The stopping potential of the metal is

Answer 1

Answer:

The stopping potential will be 2.03 V.

Explanation:

Given that,

Work function =2.1 ev

Frequency $f= 1\times10^{15}\ Hz$

The stopping potential of the metal is defined as:

$v_{0}=\dfrac{(h\nu-E_{0})}{e}$

Here,

$h\nu$=Energy of the photon on the metal

$E_{0}$=Work function of the metal

The stopping potential of the metal will be

$v_{0}=\dfrac{6.62\times10^{-34}\times10^{15}\times6.242\times10^{18}\ ev-2.1\ ev}{e}$

$v_{0}=6.62\times10^{-34}\times10^{15}\times6.242\times10^{18}-2.1$

$v_{0}=2.03\ V$

Hence, The stopping potential will be 2.03 V.