a metalic rod of length 40 cm can this rod is folded to make a rectangle of area 120 cm²
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Answer:
L*B=120cm2
by taking the lcm make the pair which product is 120 and perimeter 40.
2(l+b)=40
l+b=20
b=20-l
.substitute the value of b
l*b=120
l*(20-l)=120
20l-l2=120
20l-l^2-120=0
(Quadratic equation )
l^2-20l+120=0
(By applying shridhanacharya formula).
l is coming in negative which is wrong..
Therefore area is not possible. ..
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