Question

a metallic alloy consists of iron, copper and lea in the ratio 3:7:10 respectively, Given that the alloy has 14 kg of copper calculate:

a) the total mass of the alloy
b) the difference between the masses of iron and lead

Answer 1

Answer:

a) total mass =6kg + 14kg + 20kg = 40 kg

b) 20 kg - 6 kg = 14kg

Step-by-step explanation:

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let 7 x =14 kg

x=2kg

3x= (3×2) kg =6 kg

10x= (10×2) kg = 20 kg