A metallic ball has a radius of 9.0 cm at 0° C. Calculate the change in its volume, when it is heated to 90° C. Given that: coefficient of linear expansion of metal ball is 1.2 105 K-¹.
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Solution:
let V be the initial volume of the ball.
ΔV be the change in volume of the ball.
T be the initial temperature of the ball.
ΔT be the change in temperature of the ball.
β be the coefficient of linear expansion of metal ball.
R be the radius of the ball.
here, given in the question that
R = 9 cm = 0.09 m
β = 1.2 105 K^-1
initial temperature, T = 0°C
final temperature = 90°C
ΔT = 90-0 = 90K
now, we know
ΔV = βVΔT
ΔV = β4/3πR^3ΔT
ΔV = 1.2105*4/3*3.14*(0.09)^3*90
ΔV = 0.333 m^3
therefore, change in the volume is 0.333 m^3
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