Question

A metallic bar of length 10 cm moves in a perpendicular to the magnetic field with a velocity of 5m/sec. The induced emf in metallic bar is 25V. Then find the intensity of magnetic field.

Answer 1

Answer:

Here is your answer

Explanation:

Consider a rod of 10 cm length is moving perpendicular to uniform magnetic field as shown below.

The emf induced in the rod

ϵ=vBl

Differentiating with respect to time t

Rate of increase of induced emf=

dt

dϵ

=

dt

dv

Bl=aBl

=5×5×10

−4

×10×10

−2

=250×10

−6

=2.5×10

−4

Vs

−1

.

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