Question

A metallic bar of length 10 cm moves in a perpendicular to the magnetic field with a velocity of 5m/sec. The induced emf in metallic bar is 25V. Then find the intensity of magnetic field.

Answer 1

Answer:

$\boxed{\mathfrak{Intensity \ of \ magnetic \ field \ (B) = 50 \ T}}$

Given:

Length of metallic bar (l) = 10 cm = 0.1 m

Velocity (v) = 5 m/a

Induced motional emf in metallic bar (ɛ) = 25 V

Explanation:

Motional emf across a metallic conductor is given as:

$\boxed{ \bold{ \epsilon = Blv}}$

B $\longrightarrow$ Intensity of magnetic field

By substituting values in the formula we get:

$\rm \implies 25= B \times 0.1 \times 5 \\ \\ \rm \implies 25= B \times 0.5 \\ \\ \rm \implies B = \frac{25}{0.5} \\ \\ \rm \implies B =50 \: T$