Question

A metallic Bob of mass 2 kg is thrown from certain of 50 m reaches the

ground in 5 s. Calculate power of the metallic Bob.​

Answer 1

Answer:

Given : m=0.2kg,g=10ms

−2

,h

1

=10m,h

2

=6m.

Loss in P.E. =mg(h

1

−h

2

)

=0.2×10×10(10−6)

=0.2×10×4=8J