a metallic chain of 1cm long lies on a horizontal surface of a table. The chain starts sliding on the table if 25cm or more hangs over the edge of the table. The coreect value of coefficient offriction between the 5able and chain is?
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let the friction coefficient be 'n'.
now, till 25cm of chain hangs the chain does not slides . So what 25cm of chain hangs it will be the limiting case, means net force will be zero.
frictional force = weight of 25cm chain
( let the mass per unit length of chain be 't' )
n × 0.75 × t × g = 0.25 × t × g
n = 0.25/0.75
n = 1/3
( here 'g' is acceleration due to gravity )
now, till 25cm of chain hangs the chain does not slides . So what 25cm of chain hangs it will be the limiting case, means net force will be zero.
frictional force = weight of 25cm chain
( let the mass per unit length of chain be 't' )
n × 0.75 × t × g = 0.25 × t × g
n = 0.25/0.75
n = 1/3
( here 'g' is acceleration due to gravity )
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