A metallic container is in the shape of a frustum of a cone.if the diameter of the circular ends are 20cm and 16cm respectively and the vertical height is 42cm Find the volume of the container also find the cost of milk it can hold if the rate of milk is 40 per litre
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volume of frustum=πh/3*(R^2+rR+r^2)
=(22*42/21)*(100+64+80)
=44*244
=10736 cm3= 10.736
cost= 10.736*40=429.44
=(22*42/21)*(100+64+80)
=44*244
=10736 cm3= 10.736
cost= 10.736*40=429.44
sabarinathcs:
thank you very much
are you sure abt your answer becozz i also got the same result after trying it
i am also verified 3 times
ohh thankyou very much ...............
welcome
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