Question

A metallic cube of edge 2.5 cm is melted and recast into the form of cuboid of base 1.25 cm × 0.25 cm find increase in the surface area​

Answer 1

vol. of the cube = 2.5^3=15.625cm3

height of cuboid=15.625 / 1.25xo.25 = 50cm

SA of cube = 6a ^2 = 6x2.5^2 = 37.5cm2

SA of cuboid=2lb +2h (I+b)

2x1.25xo.25 +2x50 (1.25 +0.25)

125.625 cm2

Answer 2

Answer:

vol. of cube=(a³)

(2.5)³=15.625 cm³

h of cuboid=15.625/1.25×0.25=50 cm

SA of cube=(a)³=6×2.5²=37.5 cm²

SA of cuboid=2lb+2h×(l+b)

=2×1.25×0.25+2×50 (1.25+0.25)

=125.625 cm²

hope this helps❣