Question

A metallic cylinder has lenght 10 cm and area of cross section 2 cm^2 . if its resistance is 20 ohm calculate its resistivity

Answer 1

Electricity

Given

Length of metallic cylinder (l) = 10

Area of cross section (A) = 2 cm^2

Resistance (R) = 20 ohm

We know that

R = p.(l/A) [ p = resistivity]

So,

20 = p.(10/2)

=> 20 = p.5

=> p = 4 ohm cm

So the resistivity of the metallic cylinder is 4 ohm cm

[Answer is in CGS]

As 1 ohm cm = 0.01 ohm m

so the answer in MKS or SI will be 0.04 ohm m

That’s it

Hope it helped

(O_o)

Answer 2

Answer:

Resistivity=(resistance×area)/length

=(20×2×10^-4)/0.1

40×10^-3 ohm metres

Hope it helps