a metallic cylinder has radius 3 centimetre and height 5 centimetre to reduce its weight conical hole is drilled in the cylinder the conical whole has a radius of 3 by 2 cm and its depth is 8.9 CM calculate the ratio of the volume of metal left in the cylinder to the volume of metal taken out in conical shape. please solve in copy
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Volume of metal B=
3
1
πr
1
2
h
1
=
3
1
π(
2
3
)
2
(
9
8
)=
3
2π
Volume of metal A=πr
2
h−
3
1
πr
1
2
h
1
=
3
π
(3r
2
h−r
1
2
h
1
)
=
7×3
22
(3×9×5−
4
9
×89)=
21
22
(135−2)=
21
22×133
=139.33 cm
3
ratio =
2π
139.33×3
=
3.14
209
=
π
209
=
22
209×7
=
2
133
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