Question

A metallic cylinder has radius 3 cm and height 5 cm. It is made of metal A. To reduce its weight, a conical hole is drilled in the cylinder. It is completely filled with lighter metal B. The conical hole has a radius of 3/2 cm and its depth is 8/9 cm. Calculate the ratio of the volume of the metal A to the metal B. I solved it but the answer is wrong. My method was: 3.14*3*3*5=1/3*3.14*1.5*1.5*8/9 5=1/3*2/9 5= 2/27 135:2 is the final answer but the textbook shows 133:2. please help me.

Answer 1

Given: Radius of cylinder = 3cm and height = 5cm
Therefore, total Volume of cylinder =

and radius of cone = cm and height = cm
volume of cone =

therefore, acc. to the question,
Volume of cylinder = total volume of cylinder – volume of cone

Now,

Answer 2

The answer is in the image