Question

A metallic cylinder has radius 3 cm and height 5 cm. To reduce its weight, a conical hole is drilled in the cylinder. The conical hole has a radius of 3/2 cm and its depth is 8/9 cm. Calculate the ratio of the volume of metal left in the cylinder to the volume of metal taken out in conical shape.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Volume of metal B=

3

1

πr

1

2

h

1

=

3

1

π(

2

3

)

2

(

9

8

)=

3

2π

Volume of metal A=πr

2

h−

3

1

πr

1

2

h

1

=

3

π

(3r

2

h−r

1

2

h

1

)

=

7×3

22

(3×9×5−

4

9

×89)=

21

22

(135−2)=

21

22×133

=139.33 cm

3

ratio =

2π

139.33×3

=

3.14

209

=

π

209

=

22

209×7

=

2

133