Question

A metallic cylinder has radius 3 cm and height 5cm. To reduce its weight a conical hole is drilled in the cylinder the conical hole has a radius 3/2 cm and its depth is 8/9 CM.Calculate the ratio of the volume of metal left in the cylinder to the volume of metals taken out in conical shape.
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Answer 1

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volume of cylinder:-

= πr²h‎ = π(3)²•5 =45π cm³

volume of conical hole= 1/3πr²h

=1/3π•(3/2)²•8/9

=2/3π cm³

metal left in cylinder

= 45π - 2/3π = 133π/3 cm³

now,

volume of metal left

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volume of metal taken out

→ 133/3π/2/3π =133:2

Hence, volume of metal left : volume of

metal cut off = 133:2

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Answer 2

Answer:

volume of cylinder:-

= πr²h‎ = π(3)²•5 =45π cm³

volume of conical hole

= 1/3πr²h

=1/3π•(3/2)²•8/9

=2/3π cm³

metal left in cylinder

= 45π - 2/3π = 133π/3 cm³

now,

volume of metal left

volume of metal taken out

→ 133/3π/2/3π =133:2

Hence, volume of metal left : volume of metal cut off = 133:2