A metallic cylinder has radius 3cm and height 5cm. To reduce its weight,a conical hole is drilled in the cylinder. The conical hole has a radius of 1.5cm and its depth is 0.8cm. Calculate the ratio of the volume of metal left in the cylinder to the volume of metal taken out in conical shape
Answers
Answered by
1
Radius of cylinder R= 3cm
Height of cylinder H= 5cm
Radius of cone r = 1.5cm
height of cone h= 0.8cm
Volume of metal left = volume of cylinder - volume of cone
= πR^2H+1/3πr^2h
= 22/7(3×3×5+1/3×1.5×1.5×0.8)
=22/7(45+0.6)
= 22/7×45.6
=1003.2/7
=143.3142
= 143.314 cm^3
Volume of metal taken = 1/3 ×22/7 ×1.5×1.5×0.8
= 0.6×22/7
= 13.2/7
=1.8857
=1.886 cm^3
ratio =143.3/1.9
=143.3:1.9
Height of cylinder H= 5cm
Radius of cone r = 1.5cm
height of cone h= 0.8cm
Volume of metal left = volume of cylinder - volume of cone
= πR^2H+1/3πr^2h
= 22/7(3×3×5+1/3×1.5×1.5×0.8)
=22/7(45+0.6)
= 22/7×45.6
=1003.2/7
=143.3142
= 143.314 cm^3
Volume of metal taken = 1/3 ×22/7 ×1.5×1.5×0.8
= 0.6×22/7
= 13.2/7
=1.8857
=1.886 cm^3
ratio =143.3/1.9
=143.3:1.9
mamtamonu1696:
Hey!
answer is 1463:22
Answered by
2
I am not sure... But am getting the above answer
Attachments:
Similar questions