a metallic cylinder of diameter 5 cm and height 10/3 cm is melted and cast into sphere. what is its diameter
Answers
Given :
Diameter of the metallic cylinder = 5 cm
Radius of the metallic cylinder = r = 5/2 = 2.5 cm
Height of the metallic cylinder = 10/3 cm
Find the volume of cylinder :-
Volume of cylinder = πr²h cu. unit
= 22/7 × (2.5)² × 10/3
= 65.48 (approx)
Now,
A metallic cylinder is melted and cast into sphere.
Find the radius of sphere :-
Volume of sphere = 4/3πr³
=> 65.48 = 4/3 × 22/7 × r³
=> 65.48 × 3 × 7 = 4 × 22 × r³
=> 1375 (approx) = 88r³
=> r³ = 1375/88 = 15.625
=> r = 3√15.625 = 2.5
Diameter = Radius × 2 = 2.5 × 2 = 5 cm
Hence,
Diameter of sphere = 5 cm
_______________________
✯ @shivamsinghamrajput ✯
Answer:
The diameter of the the sphere is 5 cm.
Step-by-step explanation:
It is given that a metallic cylinder of diameter 5 cm and height 10 / 3 cm is melted and cast into a sphere.
We know that if we cast anything from one state to other, it's volume can't be change.
So,
⇒ Volume of metallic cylinder = Volume of sphere
We know,
Volume of cylinder = πr^2h
And, volume of sphere = 4 / 3 πr^3
Now, let the radius of sphere be a,
Radius of the cylinder = diameter / 2 = 5 cm / 2 = 2.5 cm
= > π( 2.5 )^2 x ( 10 / 3 ) = 4 / 3 π x r^3
= > ( 2.5 )^2 x 10 / 3 = 4 / 3 x r^3
= > ( 2.5 )^2 x 10 = 4 x r^3
= > ( 2.5 )^2 x 10 / 4 = r^3
= > 6.25 x 5 / 2 = r^3
= > 15.625 = r^3
= > ∛15.625 = r
= > 2.5 = r
= > 2 x 2.5 cm = 2 x r
= > 5 cm = diameter
Therefore the diameter of the the sphere is 5 cm.