Math, asked by BharathPeethala3158, 1 year ago

A metallic cylinder of diameter 5 cm. and height 3*1/3 cm. is melted and cast into a sphere.What is its diameter.

Answers

Answered by nikitasingh79
51

GIVEN :

Diameter of the metallic cylinder(d) = 5 cm

Radius(R) = d/2 = 5/2 = 2.5 cm

Height of the metallic cylinder(h) = 3 1/3 cm = 10/3 cm


Let radius of sphere is r cm.

The metallic cylinder is melted and cast into a sphere. So, the volume of the metallic cylinder and the sphere will be same.

Volume of the metallic cylinder =Volume of sphere

πR²h = 4/3πr³

π× 2.5× 2.5×10/3 = 4/3×π× r³

6.25 × 10 = 4r³

r³ = 62.5/4

r³ = 15.625

r =³√15.625

r = 2.5

Radius of sphere is 2.5 cm

Diameter of the sphere = radius × 2 = 2.5× 2 = 5 cm

Hence ,the Diameter of the sphere = 5 cm.


HOPE THIS WILL HELP YOU..


Answered by nikitasingh79
41

GIVEN :

Diameter of the metallic cylinder(d) = 5 cm

Radius(R) = d/2 = 5/2 = 2.5 cm

Height of the metallic cylinder(h) = 3 1/3 cm = 10/3 cm


Let radius of sphere is r cm.

The metallic cylinder is melted and cast into a sphere. So, the volume of the metallic cylinder and the sphere will be same.

Volume of the metallic cylinder =Volume of sphere

πR²h = 4/3πr³

π× 2.5× 2.5×10/3 = 4/3×π× r³

6.25 × 10 = 4r³

r³ = 62.5/4

r³ = 15.625

r =³√15.625

r = 2.5

Radius of sphere is 2.5 cm

Diameter of the sphere = radius × 2 = 2.5× 2 = 5 cm

Hence ,the Diameter of the sphere = 5 cm.


HOPE THIS WILL HELP YOU..



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hukam0685: yes ,the same question is in my mind
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