A metallic cylinder of diameter is 5cm and height is 10/3 cm. is melted and cast in to a sphere....what is its diameter
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Diameter of the metallic cylinder = 5 cm
Radius = 5/2 = 2.5 cm
Height of the metallic cylinder = 3 1/3 cm = 10/3 cm
Volume of the metallic cylinder = πr²h
⇒ 22/7*2.5*2.5*10/3
⇒ 1375/21
Volume of the metallic cylinder = 65.476 cu cm
The metallic cylinder is melted and cast into a sphere. So, the volume of the metallic cylinder and the sphere will exactly same.
Volume of sphere = 4/3πr³
⇒ 65.476 = 4/3*22/7*r³
⇒ 88r³ = 65.476*21
⇒ 88r³ = 1374.996 or 1375 (Approx)
⇒ r³ = 1375/88
⇒ r³ = 15.625
⇒ r = ∛15.625
⇒ r = 2.5
Hence, the radius of the sphere is 2.5 cm.
Then, diameter of the sphere = 2.5*2
= 5 cm
Radius = 5/2 = 2.5 cm
Height of the metallic cylinder = 3 1/3 cm = 10/3 cm
Volume of the metallic cylinder = πr²h
⇒ 22/7*2.5*2.5*10/3
⇒ 1375/21
Volume of the metallic cylinder = 65.476 cu cm
The metallic cylinder is melted and cast into a sphere. So, the volume of the metallic cylinder and the sphere will exactly same.
Volume of sphere = 4/3πr³
⇒ 65.476 = 4/3*22/7*r³
⇒ 88r³ = 65.476*21
⇒ 88r³ = 1374.996 or 1375 (Approx)
⇒ r³ = 1375/88
⇒ r³ = 15.625
⇒ r = ∛15.625
⇒ r = 2.5
Hence, the radius of the sphere is 2.5 cm.
Then, diameter of the sphere = 2.5*2
= 5 cm
Anonymous:
Yes sir..
Answered by
1
There is a basic thing you need to know that if volume of sphere always remains same when melted and changes its shape .
Volume of cylinder = volume of sphere
4/3 π r²h = 4/3 π r³
h = 4/3 π
r = 3/4 h
r = 3/4 * 10/3
r = 10/4
= 2.5
Volume of cylinder = volume of sphere
4/3 π r²h = 4/3 π r³
h = 4/3 π
r = 3/4 h
r = 3/4 * 10/3
r = 10/4
= 2.5
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