A metallic pipe is 0.7 cm thick. Inner radius of the pipe is 3.5cm and length is 5 dm . find its total Surface area.
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Step-by-step explanation:
that would be the area of the inner cylinder, plus the area of the outer cylinder, plus the area of the two rings at the end. So, if
R = outer radius
r = inner radius
h = length of pipe
the total area is
2πrh + 2πRh + π(R^2-r^2)
= 2πh(r+R) + π(R+r)(R-r)
= π(R+r)(2h+R-r)
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