Question

A metallic pipe is 0.7 cm thick. Inner radius of the pipe is 3.5cm and length is 5 dm . find its total Surface area.

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Answer 1

Step-by-step explanation:

that would be the area of the inner cylinder, plus the area of the outer cylinder, plus the area of the two rings at the end. So, if

R = outer radius

r = inner radius

h = length of pipe

the total area is

2πrh + 2πRh + π(R^2-r^2)

= 2πh(r+R) + π(R+r)(R-r)

= π(R+r)(2h+R-r)