Question

a metallic pipe is 0.7 CM thick inner radius of the pipe is 3.5 cm and length is 5 cm find its total surface area and total surface area is equal to inner surface area + outer surface area + area of two rims​

Answer 1

Answer:

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Step-by-step explanation:

the area of the inner cylinder, plus the area of the outer cylinder, plus the area of the two rings at the end. So, if

R = outer radius

r = inner radius

h = length of pipe

the total area is

2πrh + 2πRh + π(R^2-r^2)

= 2πh(r+R) + π(R+r)(R-r)

= π(R+r)(2h+R-r)

Total surface area = inner curved surface area + outer curved surface area + area of 2 rings

We will consider ,

R=outer curved surface area

r=inner curved surface area

h=given lenght

=2πRh + 2πrh + πR^2 + πr^2

=π(r +R )+(2h + R-r )

After solving with values we will get the total surface area as 253.88 cm ^2

answer is 2453.88cm^2