Question

A metallic pipe is 0.7 cm thick. Inner radius of the pipe is 3.5 cm and length is
5 dm. Find its total surface area.
[Hint: Total surface area = Inner surface area + Outer surface area + Area of two rims]​

Answer 1

Step-by-step explanation:

Inner radius = 3.5 cm and outer radius = 4.2 cm

Length = 5 dm = 50 cm

Surface area of inside of pipe = (circumference)(length) = 2π(3.5 cm)(50 cm)

= 350π cm2

Surface area of outside of pipe = 2π(4.2 cm)(50 cm) = 420π cm2

Surface area of each end of pipe = outer area - inner area

= π(4.2 cm)2 - π(3.5 cm)2 = 5.39π cm2

Total surface area = 2(5.39π) cm2 + 350π cm2 + 420π cm2 = 775.39π cm2

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Answer 2

Answer:

Thickness of pipe = h = 0.7 cm Inner radius = r = 3.5 cm

External radius = R =r+h= 3.5 + 0.7 = 4.2 cm Length = 5 dm = 50 cm

Total surface area of cylinder or pipe = 2n(r + R) = (h+R-D)

=2 x 22/7 (3.5+ 4.2) (50 + 4.2 - 3.5)

= 2453.88 cm^2

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