A metallic pipe is 0.7cm thick. Inner radius of the pipe is 3.5cm and length is 5dm. Find its total surface area
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T.S.A OF MATELLIC PIPE=
we know that pipe is open from its both
ends so we find the c.s.a of pipe
L=5dm=50cm
0.7cm thick
Inner radius =3.5cm
So, total redii=3.5+0.7=4.2cm
=2pieRH
=2*22/7*4.2*50
=44/7*210
=1320 cm square.
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inner radius of the pipe (r )= 3.5cm
External radius of the pipe (R ) = (3.5+ 0.7 )cmor,4.2cm
length=5dm or,50cm
We know,
Total surface area of pipe = 2π (r+ R ) ( h+ R - r)
or, Total surface area of pipe= 2x22/7(3.5+4.2)(50+4.2-3.5)
= 44/7 x 7.7 x 50.7
=2453.88cm^2
So the answer should be 2453.88cm^2