Question

a metallic pipe is 77 cm long, the inner diameter of cross section is 4 m and outer diameter is 4.8 m find total surface area ?

Answer 1

Surface Area of Outer circle = 2πr1h =2×22/7×2.4×.77= (44×24×11)/1000=11.616 sq m


Surface Area of inner circle = 2×πr2×h
=2×22/7 ×2×.77= 9.680

2×Area of Base = 2×22/7(2.4^2 -2^2)
___________= 44/7 ×( 5.76- 4)
___________ = 11.0628


Total Surface Area of the pipe =
Inner Surface A + Outer Surface Area+A of Base

9.680+ 11.616+ 11.0628 =32.3588 sq m