a metallic pipe whose internal and external diameter are 8 cm and 6 CM has a length of 2.1 M find the volume of the metal
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External diameter, D = 8cm ; External radius, R = D/2 = 4cm
Internal diameter, d = 6cm ; Internal radius, r = d/2 = 3cm
length of the pipe = 2.1 m = 210 cm = h
volume of metal = outer volume - inner volume
= π R2h - π r2h = πh[R2 - r2]
Internal diameter, d = 6cm ; Internal radius, r = d/2 = 3cm
length of the pipe = 2.1 m = 210 cm = h
volume of metal = outer volume - inner volume
= π R2h - π r2h = πh[R2 - r2]
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22/7*2.1(8*8-6*6)
22*0.3(28)
6.6*28
=184.4 is the answer.....
22*0.3(28)
6.6*28
=184.4 is the answer.....
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