A metallic right circular of radius 6 cm and height 14 cm is melted and recast into three sphere. If the radio of two of these spheres are 2 cm and 3 cm , find the radius of the third.
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Step-by-step explanation:
volume of cylinder = πr 2h
= πx6^2 x 14=504πcm3
3 spheres vols.
4/3πri^3+4/3πr 2^3+4/3πr 3^3
4/3πx2^3+4/3πx3^3+4/3πr 3^3
4/3π(8+27+r3^3)
504π = 4/3π(35+r3^3)
35+r3^3=504πx3/4π
35 +r3^3=I26x3
35 +r3^3=378
r3^3=378-35
= 343
r = 3v343
r = 7cm
Radius of the 3rd sphere = 7 Cm
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