A metallic rod breaks when strain produced is 0.2%. The Young's Modulus of the materials of the rod is .What should be its area of cross-section to support a load of 104N
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Answered by
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From Young’s Modulus formulae:
Y = Fl’/Al
where l’ = 2l/1000
putting all the values we get,
7 x 10^9 = 10^4 * 2l/1000*A*l
solving we get,
A = 1/1400 m^2.
Y = Fl’/Al
where l’ = 2l/1000
putting all the values we get,
7 x 10^9 = 10^4 * 2l/1000*A*l
solving we get,
A = 1/1400 m^2.
Answered by
0
Explanation:
7.15*10^-4m^2
it is the coreect answer
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