Question

A metallic rod MN of length l = 80cm, kept in a uniform magnetic field of flux density B=0.5T,
on two parallel metallic rail P and Q. calculate the emf that will
be induced between its two ends, when it is moved towards right
with a constant velocity V of 36km​

Answer 1

Given, B = 0.5T

l = 80cm = 80/100 = 0.8m

v = 36 km = 36 × 5/18 = 2 × 5 = 10 m

We know, emf (e) = Blv

e = 0.5 × 0.8 × 10 = 4