Question

A metallic scale is calibrated at 30^0c. The length of rod measured using this scale at 10^0c is 20cm. The actual length of the rod is

Answer 1

Answer:

20.01

Step-by-step explanation:

la=lm(1-(as-ao)dT)

where la=actual length

           lm=measured length

           as=linear coefficient of scale

          ao=linear coefficient of object

          dT=temperature difference

substituting the values, we get

la=20(1-[(.25-.4)10^-4 ] 20)

la=20(1+.15 . 10^-4. 20)

la=20(1+.0003)

la=20.01cm

hope this helps