Question

A metallic sheet is of a rectangular shape with dimensions 48*36m. From each it's corners, a square is cut off so as to make an open box. If the length of the square is 8m, the volume of the box is

Answer 1

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Answer 2

$\sf{\underline{We\:know\:that:}}$

Length of the metallic sheet ${= 48\:m}$

Breadth of the metallic sheet ${= 36\:m}$

$\sf{\underline{When:}}$

A square of 8 m is out off from each corner to form an open box,

$\sf{\underline{Then:}}$

Length of the open box:

$l = 48 \: m - 8 \: m - 8 \: m$

$l = 48 \: m - 16 \: m$

$l = 32 \: m$

Breadth of the open box:

$b = 36 \: m - 8 \: m - 8 \: m$

$b = 36 \: m - 16 \: m$

$b = 20 \: m$

Height of the open box:

h = side of the out off square

h = 8 m

Volume of the open box:

$\implies$ $l \times b \times h$

$\implies$ $32 \: m \times 20 \: m \times 8 \: m$

$\implies$ $32 \: m \times 160 \: m$

$\implies$ $5120 \: {m}^{3}$

$\sf{\underline{Thus:}}$

The volume of the open box is $5120 \: {m}^{3}$