Question

a metallic sheet of rectangular shape of length 48 cm and 36 CM square of 8 cm is cut off an open made is folding by remaining sheet find the volume of the open box​

Answer 1

ANSWER:-

Given:

A metallic sheet of rectangle shape of length 48cm & 36cm. A square of 8cm is cutoff.An open is made of the remaining sheet.

To find:

The volume of the open box.

Explanation:

We have,

• Length of the metallic rectangular sheet,l= 48cm
• Breadth of the metallic rectangular sheet,b= 36cm

When a square 8cm is cutoff from the rectangular sheet, we get;

⇒ New length of the rectangular sheet= [48- (2×8)]cm

⇒ New length of the rectangular sheet= [48- 16]cm

⇒ New length of the rectangular sheet= 32cm

&

⇒ New breadth of the rectangular sheet= [36-(2×8)]cm

⇒ New breadth of the rectangular sheet= [36-16]cm

⇒ New breadth of the rectangular sheet= 20cm

• Height of the rectangular sheet is 8cm.

We know that, volume of the cuboid = lbh cubic units

Therefore,

⇒ The volume of the open box= Length × Breadth× Height

⇒ The volume of the open box= [32 × 20 ×8]cm³

⇒ The volume of the open box= 5120cm³.