Physics, asked by mishraajeet9648, 1 month ago

A metallic shell having inner radius R1 and outer radii R2 has a point charge Q kept inside the cavity. Electric field in the region R1 < r < R2 where r is the distance from the centre is given by a) depends on the value of r b) Zero c) Constant and nonzero everywhere d) None of the above​

Answers

Answered by ritu633parna
5

Explanation:

hope this is helpful for you. mark me as a brainleist please

Attachments:
Answered by Anonymous
5

a) depends on the value of r

As Q charge is present inside the cavity that is inside the sphere, therefore it will create -Q charge in the inner surface of the metallic shell. .The charge on the outer surface of the metallic sphere will be increased by +Q because of the induction through the -Q charge that is present in the inner surface.

Now for the calculation of electric field at some point r in the region R1 < r < R2, where r is the distance from the centre

The electric field due to the charges Q and the charge that was induced inside the shell will cancel each other and will be zero.

Therefore, net electric field on that point will be because of the Q charge that is induced outside the shell and it will be

E= 1/4π€0(Q/r^2)

Similar questions