A metallic solid ball of radius 28cm is melted and converted into small solid balls of radius 7cm each .find the number of small balls so formed .
Answers
Answer:
Step-by-step explanation:
Volume of the solid metallic ball = 4/3*22/7*r^3
=(16*22*28*28)/3 cms cube (or we can write as 275968/3 but the previous value would be easier to solve with)
Volume of small balls=4/3*22/7*7*7*7
=(4*22*7*7)/3 cms cube (or 4312/3 )
No of balls formed= Vol of Solid ball/ Vol of small balls
= (16*22*28*28/3)*(3/4*22*7*7) ...[Taking reciprocal and multiplying]
Everything will cancel out and we get
4*4*4=64 Ball
I hope it helps
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Answer:
Step-by-step explanation:
Let the no. of small balls be 'X'
Given:-
Radius of Big ball(r1)=28cm
Radius of small ball(r2)=7cm
Volume of = X (Volume of small ball)
Big ball
4/3 π(r1)^3 = X{4/3 π(r2)^3}
(canceling 4π/3 both sides}
28×28×28=X(7×7×7)
X = 28×28×28
---------------
7×7×7
=4×4×4
______
=|64 balls|
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