A metallic solid cylinder of 14 cm diameter and 32 cm height is melted into 77 solid cubes of
equal size, then the edge of each cube must be
Answers
Answer :-
Edge of each cube must be 4 cm.
Explanation :-
Diameter of the solid cylinder (d) = 14 cm
So Radius of the solid cylinder (r) = d/2 = 14/2 = 7 cm
Height of the solid cylinder (h) = 32 cm
Volume of the solid cylinder = πr²h
= (22/7) * 7² * 32
= (22 * 7 * 32 )
Let the edge of each solid cube be 'a' cm
Volume of each solid cube = a³ cm³
Volume of 77 solid cubes. 77(a³) = 77a³ cm³
Given
Solid cylinder is casted into 77 solid cubes of equal size
i.e Volume of solid cylider = Volume of 77 solid cubes
⇒ 22 * 7 * 32 = 77a³
⇒ (22 * 7 * 32)/77 = a³
⇒ (22 * 32)/11 = a³
⇒ (2 * 32) = a³
⇒ 64 = a³
⇒ 4³ = a³
⇒ 4 = a
⇒ a = 4
∴ the edge of each cube must be 4 cm.
Edge of each must be 4 cm
Given :-
- Diameter of the metallic cylinder is 32 cm
- Height of the metallic cylinder is 32 cm
To find :-
- The edge of 77 solid cubes formed by melting the metallic cylinder.
Solution :-
Since, the metallic cylinder is melted to form 77 solid cubes the volume of the both shapes will be equal.
Where, r = radius of the cylinder
h = height of the cylinder
So, first we will calculate the radius of the cylinder.
Radius of the cylinder = 7 cm
Now block in the values in the formula for volume of a cylinder,
-----> (1)
•°• Volume of cylinder = 4928 cm³
Mentioned above when a particular shape is melted and given a new shape, the volume of the initial shape is equal to the volume of the shape formed after melting.
Let the edge of the cube be x
So as per the statement, we can write,
Number of solid cubes formed is 77
---> From (1)
=
=
³√64 =