A metallic solid cylinder of height 1 metre and diameter15cm has been melted and recast in to spheres each of diameter 5cm . how many such spheres will be obtained
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volume of metallic cylinder=pi*r*r*h
22/7*100*7.5*7.5=123750/7cm^3
no.of spheres*volume of 1 sphere=volume of cylinder
y*4/3*pi*r*r*r=pi*r*r*h
y*4/3*2.5*2.5*2.5*22/7=123750/7
y=123750*7*3/4*22*2.5*2.5*2.5
y=270
therefore, no.of spheres is 270
22/7*100*7.5*7.5=123750/7cm^3
no.of spheres*volume of 1 sphere=volume of cylinder
y*4/3*pi*r*r*r=pi*r*r*h
y*4/3*2.5*2.5*2.5*22/7=123750/7
y=123750*7*3/4*22*2.5*2.5*2.5
y=270
therefore, no.of spheres is 270
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the h=1m=100cm
r=15/2=7.5cm
R=5/2=2.5
volume of cylinder pie x r x r x h and volume of sphere 4/3pie x R xRxR
by dividing this both pie x r x r x h / 4/3 pie x R xRxR
we get ans 270 cm^3
r=15/2=7.5cm
R=5/2=2.5
volume of cylinder pie x r x r x h and volume of sphere 4/3pie x R xRxR
by dividing this both pie x r x r x h / 4/3 pie x R xRxR
we get ans 270 cm^3
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