Question

A metallic solid of volume 1m3 is melted and drawn into the form of a wire of diameter 3.5 mm. Find the length of the wire so drawn.
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Answer 1

Answer:

length of wire = 103896.1(please check the calculation if it is wrong then follow the process)

Step-by-step explanation:

volume would remain unchanged

volume of solid = volume of wire

1=πr^2h(wire is in the form of cylinder and volume of cylinder is πr2h)

1=22/7×(3.5/2)×(1/1000)×(3.5/2)×(1/1000)×h. (radius=diameter/2)(mm to m change by multiplying with 1/1000)

1=11×0.5×1.75×(1/1000000)×h

1×1000000/9.625=h

h=1000000/9.625

h=103896.1 m

Answer 2

Step-by-step explanation:

solution: Let the length of the wire be x mm

You can observe that wire is of the shape of a right circular cylinder.

Its diameter = 3.5mm

So, its radius = 3.5/2 * mm = 35/20 = 7/4 * mm

length of wire will be treated as the height of the cylinder.

So, volume of the cylinder = r²h

= 22/7 * 7/4 * 7/4 * xm * m ^ 3

But the wire has been drawn from the metal of volume 1 m³

Therefore,

22/7 ×7/4 × 7/4 x/100000000 = 1 (since 1 m = 1000 mm)

X = 1×7×4×4x1000000000/22×7×7 mm.

= 1600000000/154

this ,length ofthe wire = 1600000000/154000 m

= 103896 m (approx)

that is Answer..