a metallic specific resistance is 40 x 10 raise to power minus 8 ohm metre to make a coil for a wire having to multiply 10 raise to the power minus 4 metre square cross section area how much length of wire is required by the resistance of a metal wire is 4.8 Ohm
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Given conditions,
Resistivity(ρ) = 1.6 × 10⁻⁸ Ω-m.
Cross-sectional Area(A) = 20 × 10⁻⁴ cm² = 20 × 10⁻⁸ m²
Resistance(R) = 10 Ω
Using the formula,
ρ = RA/l
Thus, l = RA/ρ
Thus, l = 10 × 20 × 10⁻⁸/1.6 × 10⁻⁸
l = 10 × 200/16
l = 10 × 50/4
l = 5 × 25
l = 125 m.
Hope it helps.
Resistivity(ρ) = 1.6 × 10⁻⁸ Ω-m.
Cross-sectional Area(A) = 20 × 10⁻⁴ cm² = 20 × 10⁻⁸ m²
Resistance(R) = 10 Ω
Using the formula,
ρ = RA/l
Thus, l = RA/ρ
Thus, l = 10 × 20 × 10⁻⁸/1.6 × 10⁻⁸
l = 10 × 200/16
l = 10 × 50/4
l = 5 × 25
l = 125 m.
Hope it helps.
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