Question

A metallic sphere if radius 9cm is melted to recast into the shape of a cylinder of radius 6cm find the height of cylinder

Answer 1

Step-by-step explanation:

Volume of sphere = Volume of cylinder

$\frac{4}{3}\pi {r}^{2} = \pi {r}^{2}h$

$\frac{4}{3} \pi {9}^{2} = \pi {6}^{2}h$

$4 \times 3 \times 9 = 6 \times 6 \times h$

$h = \frac{4 \times 3 \times9 }{6 \times 6}$

$h = 3 \: cm$

Answer 2

Answer:

Step-by-step explanation:

volume of s sphere=4πr³

                                   3

                                = volume of cylinder

                                =πR²h

                        4πr³=πR²h

                        3

                      4×9×9×9=6×6×h

                          3

                     4×3×9×9=h

                       6×6

                     h=27cm