Question

a metallic sphere of radius 2.0 cm is completely immersed in water.find the force buoyancy on it

Answer 1

We know that v = 4/3 * pi * r * r * r 

                           = 4/3 * 22/7 * 0.02 * 0.02 * 0.02

                           = 1.67m^3

We know that buoyancy force = dgv

                                                   = 997 * 10 * 1.67

                                                   = 16649.9 N


Hope this helps!

Answer 2

The buoyancy force on the metallic sphere is 0.328 N.

Explanation:

The buoyancy force on the metallic sphere is given by

$F=d_{w} \times g\times V$

Here d_{w}  is the density of the water, g is the acceleration due to gravity and V is the volume of the metallic sphere.

The volume of the metallic sphere is

$V=\frac{4}{3} \pi r^{3}$

Given, r = 2 cm = 0.02 m.

So, $V=\frac{4}{3} \times3.14\times (0.02m)^{3}$

$V=33.5\times 10^{-6} m^{3}$

The density of the water, $d_{w} =1000kg/m^{3}$.

Substitute the given values, we get buoyancy force

$F=1000kg/m^3\times9.8m/s^2\times 33.5\times 10^{-6} m^{3}$

F = 0.328 N.

Thus, buoyancy force on the metallic sphere is 0.328 N.

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Topic : buoyancy force

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