Question

A metallic sphere of radius 2 cm is completely dipped in water. Find the force of buoyancy acting on it.

Answer 1

Upthrust = weight of the water replaced
Volume of sphere = 4/3pi r ^3
= 4/3 * 22/7 * 2*2*2
= 32*22/21
= 704/21

So mass = density x volume
= 1 gm/cc x 704/21 cc
704/21 gm
Weight = 704/21 x g
=33.52 x 10
= 335.23 newton


Hope so it’s correct I gave a try sooty if you got that problematic

Answer 2

force of buoyancy = volume immersed × density ×g

= 4/3 pie (0.02)^3 × 1000g

= 4 ×3.14 × 8 × 1/3000 g

= 0.33N