Question

A metallic sphere of radius 21 cm melted into 27 sphere. Find surface are of smaller sphere

Answer 1

here is your step wise answer friend!!!,

Volume of sphere= \frac {4}{3} \pi r^{3}=34​πr3 

Let the radius of Large sphere be R

and radius of small equal 27 spheres be r

Volume of Large sphere = Volume of all 27 Spheres 

\frac {4}{3} \pi R^{3} = 27 × \frac {4}{3} \pi r^{3}34​πR3=27×34​πr3 

Here R = 21

Therefore ,

21^{3} = 27 × r^{3}213=27×r3 

r^{3} = 7^{3}r3=73 

r = 7 cm

Surface area of sphere = 4 \pi r^{2}4πr2 

Surface area of 1 small sphere = 4 × \frac {22}{7} × 7^{2} = 616 cm^{2}4×722​×72=616cm2

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